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<p>
如果 $a \ne 0$, 则方程 \(ax^2 + bx + c = 0\) 有两个不同的根
$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$
</p>

<p>大括号的例子</p>
\[ \left( \sum_{k=1}^n a_k b_k \right)^2 \leq \left( \sum_{k=1}^n a_k^2 \right) \left( \sum_{k=1}^n b_k^2 \right) \]
<p>矩阵的例子</p>
\[\mathbf{V}_1 \times \mathbf{V}_2 =  \begin{vmatrix}
\mathbf{i} &#038; \mathbf{j} &#038; \mathbf{k} \\
\frac{\partial X}{\partial u} &#038;  \frac{\partial Y}{\partial u} &#038; 0 \\               \frac{\partial X}{\partial v} &#038;  \frac{\partial Y}{\partial v} &#038; 0
\end{vmatrix}  \]

<p>积分</p>
\[ \int_0^1 x^2 {\rm d}x = \int_0^t E {\rm d}t \]
$$ \sqrt{2} $$
$$ \int_0^1 f(x) dx $$


<span id="span01"> $ {^A_B} $ </span> $ {^C_D}\}\Rightarrow $ <span id="span02"> $ C $ </span>


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